Matematika Sekolah Menengah Pertama Tolong bantu jawab kak, pake cara ya Yang perlu di kerjakan hanya no 10 saja

alejandraschaeferulv – March 07, 2023

Tolong bantu jawab kak, pake cara ya
Yang perlu di kerjakan hanya no 10 saja

Penjelasan dengan langkah-langkah:

10. B

< CAB = 180° – ( < ACB + < CBA )

< CAB = 180° – ( 90° + 30° )

< CAB = 180° – 120°

< CAB = 60°

< ACD = 180° – ( < CAB + < ADC )

< ACD = 180° – ( 60°+ 90° )

< ACD = 180° – 150°

< ACD = 30°

AD/sin ACD = AC/sin ADC

4/sin 30° = AC/sin 90°

4/½ = AC/1

AC = 4×2/1

AC = 8 cm

AC/sin B = AB/sin ACB

8/sin 30° = AB/sin 90°

8/½ = AB/1

AB = 8×2/1

AB = 16 cm

BC =√(AB² – AC²)

BC = √(16² – 8²)

BC = √(256 – 64)

BC = √192

BC = 8√3 cm

Keliling ∆ ABC = AB + BC + AC

Keliling ∆ ABC = 16 + 8√3 + 8

Keliling ∆ ABC = (24 + 8√3) cm

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